Assume there are
pigeons and
pigeon holes, and
.
If every pigeon is
in a pigeon hole, then at least one pigeon hole has more than one
pigeons.
The pigeon hole principle itself can be proven by contradiction.
Let us make the assumption that
(more pigeons than pigeon
holes). The negation of the proposition states that every pigeon
hole has at most one pigeon. Since there are only
pigeon holes,
then the number of pigeons,
, must be less than or equal to
,
or
. This contradicts our assumption that
because
is a false proposition for all
and all
.